Class 10th NCERT Maths Complete Exercise 1.2 solution in 2025 [HBSE/CBSE Board]

Class 10th NCERT Maths Complete Exercise 1.2 solution in 2025 [HBSE/CBSE Board] 

Class-10th Math Complete Exercise-1.2 Solution
Class-10th Math Complete Exercise-1.2 Solution

Class-10th
Chapter-1 (Real Numbers)
Exercise- 1.2


Que-1 Prove that √5 is irrational.

Solution-

Let us assume the contrary that √5 is Rational.
√5 = a/b [a and b are co-prime]
√5b = a
(√5b)2 = a² [Squaring both side]
5b² = a² [ a² is divisible by 5, therefore a is also divisible by 5]---------Eq(1)
Let
a = 5c [c is an integer]
5b² = (5c)²
5b² = 25c²
b² = 5c² [b² is divisible by 5, therefore b is also divisible by 5]---------Eq(2)
a and b having common factor 5.
So, Our assumption is wrong.
Therefore √5 is irrational number.

Que-2 Prove that 3+2√5 is irrational.

Solution-  

Let us assume the contrary that 3+2√5 is Rational.
3+2√5 = a/b [a and b are co-prime]
2√5 = a - 3
           b   1
2√5 = a - 3b
              b
√5 = a - 3b
           2b
Since, a and b are integers.
Therefore, a - 3b is rational.
                   2b
But we know that √5 is irrational.
So, Our assumption is wrong.
Therefore, 3+2√5 is irrational.

Que-3 Prove the following are irrational :-

(i) 1
   √2

Solution-

Let us assume that 1/√2 is rational.
1/√2 = a/b [a and b are co-prime]
b = √2 a
b/a = √2    [I not equal to R]
Since, a and b are integers.
Therefore, b/a is rational.
But we know that √2 is irrational.
So, Our assumption is wrong.
Therefore, 1/√2 is irrational.

(ii) 7√5

Solution-

Lets us assume that 7√5 is rational.
7√5 = a/b [a and b are co-prime]
√5 = a/7b [I not equal to R]
Since, a and b are integers.
Therefore, a/7b is rational.
But we know that √5 is irrational.
So, Our assumption is wrong.
Therefore, 7√5 is irrational.

(iii) 6+√2

Solution-

Lets us assume that 6+√2 is rational.
6+√2 = a/b [a and b are co-prime]
√2 = a - 6
        b   1
√2 = a - 6b    [I not equal to R]
           b
Since, a and b are integers.
Therefore, a - 6b is rational.  
                    b  

But we know that √2 is irrational.
So, Our assumption is wrong.
Therefore, 6+√2 is irrational.

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